The solubility, in moles per dm3 of 20.2 g of potassium trioxonitrate (V) dissolve in 100 g of the resulting mixture is?(K = 39, O = 16, N =14).

Answer Details

The first step to solve the problem is to calculate the molar mass of potassium trioxonitrate (V), which is given by: KNO₃ = (1 x 39) + (1 x 14) + (3 x 16) = 101 g/mol Next, we need to calculate the number of moles of potassium trioxonitrate (V) that are present in 20.2 g: moles of KNO₃ = mass / molar mass = 20.2 / 101 = 0.2 mol Now, we need to calculate the total mass of the resulting mixture. This is given by: mass of resulting mixture = mass of KNO₃ + mass of water = 20.2 + 100 = 120.2 g Finally, we can calculate the solubility of potassium trioxonitrate (V) in moles per dm³ by dividing the number of moles of KNO₃ by the volume of the resulting mixture in dm³. The volume of the resulting mixture is equal to 0.1 dm³ (since 100 g of water is equal to 0.1 dm³): solubility = moles / volume = 0.2 / 0.1 = 2.0 Therefore, the solubility of potassium trioxonitrate (V) in moles per dm³ is 2.0 mol/dm³, which corresponds to option (D).