The solubility, in moles per dm3 of 20.2 g of potassium trioxonitrate (V) dissolve in 100 g of the resulting mixture is?(K = 39, O = 16, N =14).
Answer Details
The first step to solve the problem is to calculate the molar mass of potassium trioxonitrate (V), which is given by: KNO3 = (1 x 39) + (1 x 14) + (3 x 16) = 101 g/mol Next, we need to calculate the number of moles of potassium trioxonitrate (V) that are present in 20.2 g: moles of KNO3 = mass / molar mass = 20.2 / 101 = 0.2 mol Now, we need to calculate the total mass of the resulting mixture. This is given by: mass of resulting mixture = mass of KNO3 + mass of water = 20.2 + 100 = 120.2 g Finally, we can calculate the solubility of potassium trioxonitrate (V) in moles per dm3 by dividing the number of moles of KNO3 by the volume of the resulting mixture in dm3. The volume of the resulting mixture is equal to 0.1 dm3 (since 100 g of water is equal to 0.1 dm3): solubility = moles / volume = 0.2 / 0.1 = 2.0 Therefore, the solubility of potassium trioxonitrate (V) in moles per dm3 is 2.0 mol/dm3, which corresponds to option (D).