Find the sum of the exponential series \(96 + 24 + 6 +...\)

Assessment: WAEC SSCE - Further Mathematics - 2006 (Objective) Subject: Further Mathematics

Question 1 Report

Find the sum of the exponential series \(96 + 24 + 6 +...\)

Answer Details
The given series is 96 + 24 + 6 + ... , and we need to find its sum. First, we can observe that each term in the series is obtained by dividing the previous term by 4. So, the common ratio between consecutive terms is 1/4. Let S be the sum of the series. Then we have: S = 96 + 24 + 6 + ... Dividing both sides by 4, we get: S/4 = 24 + 6 + 1.5 + ... Now, if we subtract the second equation from the first, we get: S - S/4 = 96 Simplifying, we get: 3S/4 = 96 Multiplying both sides by 4/3, we get: S = 128 Therefore, the sum of the given series is 128. So, the correct option is (B) 128.
Read lesson note on Polynomial Functions (WAEC)
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