(a) Simplify \((\frac{4}{25})^{-\frac{1}{2}} \times 2^{4} \div (\frac{15}{2})^{-2}\) (b) Evaluate \(\log_{5} (\frac{3}{5}) + 3 \log_{5} (\frac{5}{2}) - \log...

Assessment: WAEC SSCE - General Mathematics - 1999 (Essay) Subject: General Mathematics

Question 1 Report

(a) Simplify \((\frac{4}{25})^{-\frac{1}{2}} \times 2^{4} \div (\frac{15}{2})^{-2}\)

(b) Evaluate \(\log_{5} (\frac{3}{5}) + 3 \log_{5} (\frac{5}{2}) - \log_{5} (\frac{81}{8})\).

Answer Details

(a) \[\left(\frac{4}{25}\right)^{-\frac12}=\left(\frac{25}{4}\right)^{\frac12}=\frac52,\qquad 2^{4}=16,\qquad \left(\frac{15}{2}\right)^{-2}=\left(\frac{2}{15}\right)^{2}=\frac{4}{225}.\] So \[\frac52\times16\div\frac{4}{225}=40\times\frac{225}{4}=2250.\]

(b) \[\log_{5}\!\frac35+3\log_{5}\!\frac52-\log_{5}\!\frac{81}{8}=\log_{5}\!\left(\frac35\cdot\left(\frac52\right)^{3}\cdot\frac{8}{81}\right)=\log_{5}\!\left(\frac35\cdot\frac{125}{8}\cdot\frac{8}{81}\right)=\log_{5}\!\frac{25}{27}.\] Hence the value is \[\log_{5}\frac{25}{27}=2-3\log_{5}3\approx-0.048.\]

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