A body which weighs 50N in air displaces 3.7kg of water when partially immersed in water. Calculate the upthrust on the body?

Answer Details

The upthrust on a body is equal to the weight of the water displaced by the body when it is partially or fully immersed in a fluid. Given that the body weighs 50N in air and displaces 3.7kg of water, we need to first convert the mass of the water displaced to weight. Using the formula weight = mass x gravitational acceleration (g), where g is approximately 9.81 m/s^2, we have: Weight of water displaced = 3.7 kg x 9.81 m/s^2 = 36.297 N Therefore, the upthrust on the body is 36.297 N, which is closest to option B, 37.0N. Note that the upthrust on a body depends on the density of the fluid it is immersed in. If the body is less dense than the fluid, it will experience a buoyant force pushing it upwards. If the body is more dense than the fluid, it will sink. If the body has the same density as the fluid, it will remain suspended in the fluid at a constant depth.