The electronic configuration of element Z is \(1s^2\ 2s^2\ 2p^6\ 3s^2\ 3p^1\). What is the formula of the compound formed between Z and tetraoxosulphate (VI...

Assessment: JAMB UTME - Chemistry - 2019 Subject: Chemistry

Question 1 Report

The electronic configuration of element Z is \(1s^2\ 2s^2\ 2p^6\ 3s^2\ 3p^1\). What is the formula of the compound formed between Z and tetraoxosulphate (VI) ion.

_{3}

(SO

_{4}

)

_{2}

ZSO

_{4}

_{2}

_{4}

_{2}

(SO

_{4}

)

_{3}

Answer Details

Z = 1s

^{2}

^{2}

^{6}

^{2}

^{1}

∴

We have Z

^{3 +}

and SO

_{4}^{2 -}

The reaction : Z

^{3 +}

+ SO

_{4}^{2 -}

\to

_{2}

(SO

_{4}

)

_{3}

Read lesson note on Atomic Structure And Bonding (JAMB)

Atomic Structure And Bonding

View Answer

The electronic configuration of element Z is \(1s^2\ 2s^2\ 2p^6\ 3s^2\ 3p^1\). What is the formula of the compound formed between Z and tetraoxosulphate (VI...

Related Questions

Download The App On Google Playstore