Question 1 Report
An element Z contains 80% of 168 8 16 Z and 20% of 188 8 18 Z. Its relative atomic mass is
Answer Details
R.A.M of Z = 16(80100)+18(20100) 16 ( 80 100 ) + 18 ( 20 100 ) = 12.8+3.6 12.8 + 3.6 = 16.4