The oxidation state(s) of nitrogen in ammonium nitrite is/are
Answer Details
Ammonium nitrite = NH4NO2 NH+4: Let the oxidation number of Nitrogen = x x + 4 = 1 ⟹ x = 1 - 4 x = -3 NO−2: x - 4 = -1 x = -1 + 4 ⟹ x = +3. The oxidation numbers for Nitrogen in Ammonium Nitrite = -3, +3.