How many moles of oxygen molecules would be produced from the decomposition of 2.50 moles of potassium trioxochlorate (V)?

The decomposition of potassium trioxochlorate (V) can be represented by the following balanced chemical equation: 2KClO3(s) → 2KCl(s) + 3O2(g) From this equation, we can see that 2 moles of KClO3 produce 3 moles of O2. Therefore, to determine how many moles of O2 would be produced from the decomposition of 2.50 moles of KClO3, we need to set up a proportion: 2 moles KClO3 / 3 moles O2 = 2.50 moles KClO3 / x moles O2 Simplifying this proportion, we get: x = (3/2) * 2.50 = 3.75 Therefore, 3.75 moles of O2 would be produced from the decomposition of 2.50 moles of KClO3. Thus, the correct answer is option (C): 3.75.