At 25oC and 1atm, a gas occupies a volume of 1.50dm3. What volume will it occupy at 100oC and 1atm?

This question is asking for the volume of a gas at a different temperature and pressure, but with the same amount of gas (assuming ideal gas behavior). We can use the combined gas law to solve this problem: (P1 x V1) / T1 = (P2 x V2) / T2 Where P1, V1, and T1 are the initial pressure, volume, and temperature, and P2, V2, and T2 are the final pressure, volume, and temperature. Plugging in the values given in the question: (P1 x V1) / T1 = (P2 x V2) / T2 (1 atm x 1.50 dm3) / (298 K) = (1 atm x V2) / (373 K) Solving for V2: V2 = (1 atm x 1.50 dm3 x 373 K) / (298 K x 1 atm) V2 = 1.88 dm3 Therefore, the answer is 1.88 dm3, which is the first option given.