N2 2 O4 4 ? 2NO2 2 (? = -ve) From the reaction above, which of these conditions would produce the highest equilibrium yield for N2 2 O4 4 ?

N2 ${}_2$O4 ${}_4$ ? 2NO2 ${}_2$          (? = -ve)

From the reaction above, which of these conditions would produce the highest equilibrium yield for N2 ${}_2$O4 ${}_4$?

Answer Details

The highest equilibrium yield of N2O4 would be produced at low temperature and low pressure. In a chemical reaction, the position of the equilibrium can be influenced by changing the temperature or pressure. A decrease in temperature or an increase in pressure favors the side of the reaction with the fewer moles of gas (in this case, N2O4). This means that, if the temperature is low and the pressure is low, there will be more N2O4 at equilibrium, as the reaction will shift to the right to counteract the reduction in the concentration of N2O4. So, low temperature and low pressure would produce the highest equilibrium yield of N2O4.