A source of sounds produces waves in air of wavelength1.65m. If the speed of sound in air is 330ms-1 the period of vibration in seconds is

Answer Details

The speed of sound is given as 330ms^{-1}. The relationship between speed, frequency, and wavelength of a wave is given as V = fλ, where V is the speed, f is the frequency, and λ is the wavelength. Solving for frequency (f), we get f = V/λ. Substituting the values given, we have f = 330/1.65 = 200 Hz. The period of vibration is the time it takes for one complete vibration or cycle, and is given as T = 1/f. Substituting the value of frequency obtained above, we have T = 1/200 = 0.005 s. Therefore, the correct answer is 0.005.