An electron of charge 1.6 x 1019C is accelerated in vacuum from rest at zero volt towards a plate of 40KV. Calculate the kinetic energy of the electron.

Assessment: WAEC SSCE - Physics - 1988 (Objective) Subject: Physics

Question 1 Report

An electron of charge 1.6 x 10¹⁹C is accelerated in vacuum from rest at zero volt towards a plate of 40KV. Calculate the kinetic energy of the electron.

4 x 10 ²⁵J

4 x 10²¹ J

6.4 x 10²⁰ J

6.4 x 10^-15 J

2.5 x 10²⁰ J

Answer Details

To calculate the kinetic energy of the electron, we need to use the formula: K.E = qV where q is the charge of the electron and V is the potential difference. Given: q = 1.6 x 10^(-19) C V = 40 kV = 40 x 10^3 V Substituting the values in the formula, we get: K.E = (1.6 x 10^(-19) C) x (40 x 10^3 V) K.E = 6.4 x 10^(-15) J Therefore, the kinetic energy of the electron is 6.4 x 10^(-15) J. Hence the option that corresponds to this answer is: 6.4 x 10^-15 J.

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Electrostatics

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An electron of charge 1.6 x 1019C is accelerated in vacuum from rest at zero volt towards a plate of 40KV. Calculate the kinetic energy of the electron.

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