A charge of 1.0 x 10-5 Coulombs experience force of 40N at a certain point in space. What is the electric field intensity?

Assessment: WAEC SSCE - Physics - 1990 (Objective) Subject: Physics

Question 1 Report

A charge of 1.0 x 10^-5 Coulombs experience force of 40N at a certain point in space. What is the electric field intensity?

8.00 x 10⁶NC^-1

4.00 x 10⁶NC^-1

4.00 x 10^-4NC^-1

2.00 x 10^-4NC^-1

2.50 x 10^-1NC^-1

Answer Details

The electric field intensity (E) at a point in space is defined as the electric force (F) per unit charge (q) at that point. Therefore, we can use the formula: E = F/q Substituting the given values, we get: E = 40 N / 1.0 x 10^-5 C = 4.00 x 10⁶ N/C Thus, the electric field intensity at the given point in space is 4.00 x 10⁶ N/C. Therefore, the correct option is: 4.00 x 10⁶NC^-1.

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Electric Field

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A charge of 1.0 x 10-5 Coulombs experience force of 40N at a certain point in space. What is the electric field intensity?

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