How much heat is given out when a piece of iron of mass 50g and specific heat capacity 460 Jkg^{-1}k^{-1} cools from 85^{o}C to 25^{o}C?

Answer Details

The amount of heat given out by the iron can be calculated using the formula: Q = mcΔT Where Q is the heat energy transferred, m is the mass of the iron, c is the specific heat capacity of iron, and ΔT is the change in temperature of the iron. Substituting the given values, we have: Q = (0.05 kg) × (460 J/kg·K) × (85°C - 25°C) Q = 0.05 kg × 460 J/kg·K × 60°C Q = 1380 J Therefore, the amount of heat given out by the iron when it cools from 85°C to 25°C is 1380 J. Hence the correct option is (d) 1.38x10^{3}J.