The number of Hydrogen ions in 1.0\(dm^{3}\) of 0.02\(moldm^{-3}\) tetraoxosulphate(VI) acid is \([N_{A} = 6.02 \times 10^{23}]\)

Question 1 Report

\(1.2 \times 10^{22}\)

\(1.2 \times 10^{23}\)

\(2.4 \times 10^{22}\)

\(2.4 \times 10^{23}\)