A source of sound produces waves in air of wavelength 1.65m. If the speed of sound in air is 330ms−1 − 1 , the period of vibration in air is?

A source of sound produces waves in air of wavelength 1.65m. If the speed of sound in air is 330ms−1 ${}^{-1}$, the period of vibration in air is?

Answer Details

The period of vibration is the time it takes for one complete cycle of a wave to pass a fixed point. It is related to the wavelength and speed of the wave by the equation: T = λ / v where T is the period, λ is the wavelength, and v is the speed of the wave. Given the wavelength of the wave in air is 1.65 m and the speed of sound in air is 330 m/s, we can substitute these values in the above equation to get: T = λ / v = 1.65 m / 330 m/s = 0.005 s So, the period of vibration in air is 0.005 s.