A chord subtends an angle of 72º at the centre of a circle of radius 24.5m. Calculate the perimeter of the minor segment. [Take π = 227

Answer Details

From ΔOKB

sin 36° = |KB|24.5 $\frac{|\mathrm{<br>}}{}$

|KB| = 0.5878 x 24.5

 =14.4011m

Or

Length of arc = 72360∗2∗227∗24.7 $\frac{72}{360}\ast 2\ast \frac{22}{7}\ast 24.7$ 

=30.8m

Perimeter = 2(14.4011) + 30.8

= 59.6022

= 59.6m