A body of mass 200g and specific heat capacity 0.4Jg-1k-1 cools from 37oC to 31oC. Calculate the quantity of the heat released by the body.
Question 1 Report
A body of mass 200g and specific heat capacity 0.4Jg-1k-1 cools from 37oC to 31oC. Calculate the quantity of the heat released by the body.
Answer Details
The quantity of heat released by the body can be calculated using the formula:
Q = mcΔT
where Q is the quantity of heat, m is the mass of the body, c is the specific heat capacity, and ΔT is the change in temperature.
Substituting the given values:
m = 200g = 0.2kg
c = 0.4Jg^-1k^-1
ΔT = (31 - 37)°C = -6°C
Q = (0.2kg) x (0.4Jg^-1k^-1) x (-6°C)
= -0.48J
The negative sign indicates that the body released heat to the surroundings, which is the expected outcome since the body cooled down. Thus, the correct answer is 0.48J. However, none of the given options match this value exactly. The closest option is 480J, but this is off by a factor of 1000.
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