A body accelerates uniformly from rest at 2ms-2. Calculate the magnitude of its velocity after travelling 9m

Assessment: WAEC SSCE - Physics - 2007 (Objective) Subject: Physics

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A body accelerates uniformly from rest at 2ms^-2. Calculate the magnitude of its velocity after travelling 9m

4.5 ms^-1

6.0ms^-1

18.0^-1

36.0^-1

Answer Details

To solve this problem, we can use the kinematic equation: v² = u² + 2as Where: v = final velocity (what we want to find) u = initial velocity (in this case, 0 since the body starts from rest) a = acceleration (given as 2 ms^-2) s = distance travelled (given as 9m) Substituting the given values, we get: v² = 0² + 2 x 2 ms^-2 x 9m v² = 36 ms^-1 v = √(36) ms^-1 Therefore, the magnitude of the velocity of the body after travelling 9m with a uniform acceleration of 2ms^-2 is 6.0 ms^-1.

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A body accelerates uniformly from rest at 2ms-2. Calculate the magnitude of its velocity after travelling 9m

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