A body accelerates uniformly from rest at 2ms-2. Calculate the magnitude of its velocity after travelling 9m
Answer Details
To solve this problem, we can use the kinematic equation: v2 = u2 + 2as Where: v = final velocity (what we want to find) u = initial velocity (in this case, 0 since the body starts from rest) a = acceleration (given as 2 ms-2) s = distance travelled (given as 9m) Substituting the given values, we get: v2 = 02 + 2 x 2 ms-2 x 9m v2 = 36 ms-1 v = √(36) ms-1 Therefore, the magnitude of the velocity of the body after travelling 9m with a uniform acceleration of 2ms-2 is 6.0 ms-1.