A body moving with an initial velocity U accelerates until it attains a velocity of V within a time t. The distance, s covered by the body is given by the e...

Assessment: WAEC SSCE - Physics - 2007 (Objective) Subject: Physics

Question 1 Report

A body moving with an initial velocity U accelerates until it attains a velocity of V within a time t. The distance, s covered by the body is given by the expressions

s = (\(\frac{v - u}{2}\))t

s = (\(\frac{v + 2u}{2}\))t

s = (\(\frac{v + u}{2}\))t

s = (\(\frac{2v + u}{2}\))t

Answer Details

The equation that relates initial velocity, final velocity, acceleration, time and distance is given by s = ut + 0.5at^2 + \(\frac{1}{2}\) at^2. We are given that the body is moving with an initial velocity U and attains a final velocity V within time t. Hence, the acceleration of the body can be calculated using the equation: a = (V - U) / t. Now, substituting the value of acceleration in the above equation, we get: s = Ut + \(\frac{1}{2}\)(V - U)t = \(\frac{V+U}{2}\)t Therefore, the expression for the distance, s covered by the body is s = (\(\frac{V+U}{2}\))t. Hence, option (C) is the correct answer.

Read lesson note on Scalars And Vectors (JAMB)

Scalars And Vectors

View Answer

A body moving with an initial velocity U accelerates until it attains a velocity of V within a time t. The distance, s covered by the body is given by the e...

Related Questions

Download The App On Google Playstore