A motor of a corn mill machine operates on electrical energy of \(1.44 \times 10^{5}\)J. If one-quarter of the energy is wasted on sound and heat, determine...

A motor of a corn mill machine operates on electrical energy of \(1.44 \times 10^{5}\)J. If one-quarter of the energy is wasted on sound and heat, determine the efficiency of the machine.

Answer Details

The efficiency of a machine is the ratio of useful output energy to the input energy. In this case, the useful output energy is the energy used to grind corn, and the input energy is the electrical energy used to power the motor. The problem states that one-quarter of the energy is wasted on sound and heat. Therefore, the useful output energy is three-quarters (i.e., 100% - 25%) of the input energy. We can calculate the useful output energy as follows: Useful output energy = 3/4 x 1.44 x 10^5 J = 1.08 x 10^5 J Now, we can calculate the efficiency of the machine as follows: Efficiency = (Useful output energy / Input energy) x 100% = (1.08 x 10^5 J / 1.44 x 10^5 J) x 100% = 0.75 x 100% = 75% Therefore, the efficiency of the corn mill machine is 75%.