Ice of mass 50g at 0°C was completely melted by 70% of the total heat energy supplied. Calculate the total heat energy supplied [Specific latent heat of fus...

Assessment: WAEC SSCE - Physics - 2017 (Objective) Subject: Physics

Question 1 Report

Ice of mass 50g at 0°C was completely melted by 70% of the total heat energy supplied. Calculate the total heat energy supplied  [Specific latent heat of fusion of ice = 336\(Jg^{-1}\)]

Answer Details
To completely melt the ice, we need to supply heat energy to it equal to its mass multiplied by its specific latent heat of fusion. So, the heat energy required to melt the 50g of ice completely is given by: Heat energy required = mass × specific latent heat of fusion = 50g × 336 J/g = 16800 J But we know that only 70% of the total heat energy supplied was used to completely melt the ice. So, we can set up the following equation: Total heat energy supplied × 70/100 = 16800 J Simplifying the equation, we get: Total heat energy supplied = 16800 J × 100/70 = 24000 J Therefore, the total heat energy supplied is 24000 J. Answer option D is correct.

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