A body accelerates uniformly from rest at 2\(ms^{-2}\). Calculate its velocity when it has travelled a distance of 9m.

A body accelerates uniformly from rest at 2\(ms^{-2}\). Calculate its velocity when it has travelled a distance of 9m.

Answer Details

To solve the problem, we can use the following equation of motion: v^2 = u^2 + 2as where v is the final velocity, u is the initial velocity (which is zero since the body starts from rest), a is the acceleration, and s is the distance travelled. Substituting the given values into the equation, we have: v^2 = 0 + 2(2)(9) v^2 = 36 v = sqrt(36) v = 6.0 ms^-1 Therefore, the final velocity of the body when it has travelled a distance of 9m is 6.0\(ms^{-1}\).