A body accelerates uniformly from rest at 2\(ms^{-2}\). Calculate its velocity when it has travelled a distance of 9m.
Question 1 Report
A body accelerates uniformly from rest at 2\(ms^{-2}\). Calculate its velocity when it has travelled a distance of 9m.
Answer Details
To solve the problem, we can use the following equation of motion:
v^2 = u^2 + 2as
where v is the final velocity, u is the initial velocity (which is zero since the body starts from rest), a is the acceleration, and s is the distance travelled.
Substituting the given values into the equation, we have:
v^2 = 0 + 2(2)(9)
v^2 = 36
v = sqrt(36)
v = 6.0 ms^-1
Therefore, the final velocity of the body when it has travelled a distance of 9m is 6.0\(ms^{-1}\).
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