A final examination requires that a student answer any 4 out of 6 questions. In how many ways can this be done?

Assessment: JAMB UTME - Mathematics - 2006 Subject: General Mathematics

Question 1 Report

A final examination requires that a student answer any 4 out of 6 questions. In how many ways can this be done?
Answer Details
To calculate the number of ways a student can answer any 4 out of 6 questions, we can use the combination formula, which is: nCk = n! / (k! * (n-k)!) where n is the total number of items, k is the number of items to be selected, and ! represents the factorial function. In this case, we have n = 6 (the total number of questions on the exam) and k = 4 (the number of questions the student must answer). So we can calculate the number of ways to select 4 questions out of 6 using the combination formula as follows: 6C4 = 6! / (4! * (6-4)!) = (6 * 5 * 4 * 3) / (4 * 3 * 2 * 1) = 15 Therefore, the answer is 15, which means that a student can answer any 4 out of 6 questions in 15 different ways.

Download The App On Google Playstore

Everything you need to excel in your exams

Green Bridge CBT Mobile App
Personalized AI Learning Chat Assistant
200,000+ Exam Questions Across IGCSE, JAMB, WAEC & NECO
Over 3,900 Lesson Notes
Offline Support - Learn Anytime, Anywhere
Green Bridge Timetable
Literature Summaries & Potential Questions
Track Your Performance & Progress
In-depth Explanations for Comprehensive Learning