Question 1 Report
In the diagram given PQ = 10cm, PS = 8cm and < PSR is 60 while < SRQ is a right angle. Find SR
Answer Details
Draw a line perpendicular to |SR| to form |PT| in △ △ PST, cos 60 = \(\frac{|ST|}{8}\(
|PT| = 8 cos 6 = 4cm
Since |TR| = |PQ|
SR = ST + TR
= (4 + 10)cm
= 14cm
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