In the diagram given PQ = 10cm, PS = 8cm an..

Question 1 Report

In the diagram given PQ = 10cm, PS = 8cm and < PSR is 60 while < SRQ is a right angle. Find SR

\sqrt{3}

10cm

45cm

14cm

Answer Details

Draw a line perpendicular to |SR| to form |PT| in $△$ PST, cos 60 = \(\frac{|ST|}{8}\(

|PT| = 8 cos 6 = 4cm

Since |TR| = |PQ|

SR = ST + TR

= (4 + 10)cm

= 14cm