Two groups of male students cast their vote on a particular proposal. The results are as follows: In favor Against Group A 128 32 Group B 96 48 If a student...
Two groups of male students cast their vote on a particular proposal. The results are as follows:
In favor
Against
Group A
128
32
Group B
96
48
If a student is chosen at random, what is probability that he is against the proposal?
Answer Details
To find the probability that a student chosen at random is against the proposal, we need to add up the number of students from Group A and Group B who are against the proposal, and divide that by the total number of students.
The number of students against the proposal in Group A is 32, and in Group B it is 48. So the total number of students against the proposal is:
32 + 48 = 80
The total number of students in both groups is:
128 + 32 + 96 + 48 = 304
So the probability that a student chosen at random is against the proposal is:
80 / 304 = 5/19
Therefore, the answer is option (C) 5/19.