Solve the equation 2a\(^2\) - 3a - 27 = 0

Assessment: WAEC SSCE - General Mathematics - 1990 (Objective) Subject: General Mathematics

Question 1 Report

Solve the equation 2a\(^2\) - 3a - 27 = 0

Answer Details
To solve the equation 2a\(^2\) - 3a - 27 = 0, we can use the quadratic formula which is: a = (-b ± sqrt(b\(^2\) - 4ac)) / 2a In this case, we have a = 2, b = -3, and c = -27. Substituting these values into the formula, we get: a = (-(-3) ± sqrt((-3)\(^2\) - 4(2)(-27))) / 2(2) Simplifying the expression under the square root, we get: a = (-(-3) ± sqrt(225)) / 4 which gives us: a = (3 ± 15) / 4 Therefore, we have two solutions: a = 3 and a = -6/2 = -3/2 Hence, the correct option is -3, 9/2.

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