(a). \(\frac{T}{\sin 90^o}\) = \(\frac{120}{sin 135^o}\) and found T = 169.71N (b) \(\frac{R}{\sin 135^o}\) = \(\frac{120}{\sin 135^o}\) R = 120N

Question 1 Report

(a).  \(\frac{T}{\sin 90^o}\) = \(\frac{120}{sin 135^o}\) and found T = 169.71N

(b) \(\frac{R}{\sin 135^o}\) = \(\frac{120}{\sin 135^o}\)

R = 120N