A pipe closed at one end is 1.0m long. The air in the pipe is set into vibration and a fundamental note of frequency 85Hz is produced. Calculate the velocit...

Assessment: WAEC SSCE - Physics - 1992 (Objective) Subject: Physics

Question 1 Report

A pipe closed at one end is 1.0m long. The air in the pipe is set into vibration and a fundamental note of frequency 85Hz is produced. Calculate the velocity of sound in the air. (Neglect end correction).
Answer Details
The fundamental frequency of a closed pipe is given by: f = v/4L where f is the frequency, v is the velocity of sound and L is the length of the pipe. Rearranging this equation to solve for v, we get: v = 4Lf Substituting the values given in the question, we get: v = 4 x 1.0m x 85Hz v = 340.0ms^-1 Therefore, the velocity of sound in air is 340.0ms^-1. Answer: 340.0ms^-1.

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