The sum to infinity of a geometric progression is \( -\frac{1}{10} \) and the first term is \( -\frac{1}{8} \). Find the common ratio of the progression.

Assessment: JAMB UTME - Mathematics - 2012 Subject: General Mathematics

Question 1 Report

The sum to infinity of a geometric progression is \( -\frac{1}{10} \) and the first term is \( -\frac{1}{8} \). Find the common ratio of the progression.

Answer Details
Sr =  a 1 − r
− 1 10  =  1 8 × 1 1 − r
− 1 10  =  1 8 ( 1 − r )
− 1 10  =  1 8 − 8 r
cross multiply...
-1(8 - 8r) = -10
-8 + 8r = -10
8r = -2
r = -1/4

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