Question 1 Report
A given volume of methane diffuses in 20s. How long will it take the same volume of sulphur (IV) oxide to diffuse under the same conditions?
[C = 12, H = 1, S = 32, O = 16].
Answer Details
Relative molecular mass of CH4 = 12 * 1 + 4 = 16 Relative molecular mass of SO2 = 32 + 10 *2 = 64 tSO2/tCH4 = √MSO2/MCH4 t/20 = √64/16 = √4 t/20 = 2 ∴ t = 20 * 2 = 40sec
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