The p.d across a parallel-plate capacitor is 103V. If the distance between the two plates is 10cm. Calculate the magnitude of the electric field strength be...
Question 1 Report
The p.d across a parallel-plate capacitor is 103V. If the distance between the two plates is 10cm. Calculate the magnitude of the electric field strength between the plates.
Answer Details
The electric field strength between the plates of a parallel-plate capacitor is given by:
E = V/d
Where V is the potential difference across the plates, and d is the distance between the plates.
Substituting the given values, we get:
E = 10^3/0.1
E = 10^4 V/m
Therefore, the magnitude of the electric field strength between the plates is 1.0 x 10^4 V/m.
is the correct answer.
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