A 10\(\mu\)C charge moves with a velocity of 1.0 x 105 ms-1 at right angle to a uniform magnetic field of flux density 5.0 x 10-4T. Calculate the force on t...
Question 1 Report
A 10\(\mu\)C charge moves with a velocity of 1.0 x 105 ms-1 at right angle to a uniform magnetic field of flux density 5.0 x 10-4T. Calculate the force on the charge
Answer Details
The force experienced by a charged particle moving in a magnetic field is given by the formula F = Bqv, where F is the force, B is the magnetic field flux density, q is the charge on the particle, and v is the velocity of the particle.
Using the given values, we can calculate the force as:
F = Bqv
= (5.0 x 10^-4 T)(10^-5 C)(1.0 x 10^5 m/s)
= 5.0 x 10^-4 N
Therefore, the correct answer is: 5.0 x 10^-4 N.
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