If 5.00cm3 of 0.20 mol dm-3Na2CO3 was diluted with distilled water to obtain 250 cm3 solution, what is the concentration of the resulting solution?

Answer Details

To solve the problem, we need to use the formula: C₁V₁ = C₂V₂ Where C₁ is the initial concentration, V₁ is the initial volume, C₂ is the final concentration, and V₂ is the final volume. Plugging in the values we know: C₁ = 0.20 mol dm^-3 V₁ = 5.00 cm³ = 0.005 dm³ V₂ = 250 cm³ = 0.250 dm³ Solving for C₂: C₂ = (C₁V₁)/V₂ C₂ = (0.20 mol dm^-3)(0.005 dm³)/(0.250 dm³) C₂ = 0.004 mol dm^-3 Therefore, the concentration of the resulting solution is 0.004 mol dm^-3. Answer: 0.004 mol dm^-3