If 5.00cm3 of 0.20 mol dm-3Na2CO3 was diluted with distilled water to obtain 250 cm3 solution, what is the concentration of the resulting solution?

If 5.00cm³ of 0.20 mol dm^-3Na₂CO₃ was diluted with distilled water to obtain 250 cm³ solution, what is the concentration of the resulting solution?

Answer Details

To solve the problem, we need to use the formula: C₁V₁ = C₂V₂ Where C₁ is the initial concentration, V₁ is the initial volume, C₂ is the final concentration, and V₂ is the final volume. Plugging in the values we know: C₁ = 0.20 mol dm^-3 V₁ = 5.00 cm³ = 0.005 dm³ V₂ = 250 cm³ = 0.250 dm³ Solving for C₂: C₂ = (C₁V₁)/V₂ C₂ = (0.20 mol dm^-3)(0.005 dm³)/(0.250 dm³) C₂ = 0.004 mol dm^-3 Therefore, the concentration of the resulting solution is 0.004 mol dm^-3. Answer: 0.004 mol dm^-3