A rectangular packet has inner dimension 16cm by 12cm by 6cm. How many cubes of sugar of side 2cm can be neatly packed into the packet?

To solve this problem, we need to calculate the volume of the rectangular packet and the volume of each cube of sugar, and then divide the volume of the packet by the volume of each cube. The volume of the rectangular packet is: $$V_{packet} = 16 \text{cm} \times 12 \text{cm} \times 6 \text{cm} = 1152 \text{cm}^3$$ The volume of each cube of sugar is: $$V_{cube} = 2 \text{cm} \times 2 \text{cm} \times 2 \text{cm} = 8 \text{cm}^3$$ To calculate how many cubes of sugar can be packed into the packet, we divide the volume of the packet by the volume of each cube: $$\frac{V_{packet}}{V_{cube}} = \frac{1152 \text{cm}^3}{8 \text{cm}^3} = 144$$ Therefore, 144 cubes of sugar of side 2cm can be neatly packed into the rectangular packet. Hence, the correct answer is 144.