A fair die is tossed once, what is the probability of obtaining neither 5 or 2
Answer Details
A fair die has six equally likely outcomes, which are the numbers 1, 2, 3, 4, 5, and 6.
To find the probability of obtaining neither 5 nor 2, we first need to find the number of outcomes that satisfy this condition.
There are four outcomes that are not 5 or 2, which are 1, 3, 4, and 6.
Therefore, the probability of obtaining neither 5 nor 2 is the number of outcomes that satisfy this condition divided by the total number of possible outcomes, which is 4/6 or 2/3.
Thus, the answer is option (B), \(\frac{2}{3}\).
To summarize, the probability of obtaining neither 5 nor 2 when a fair die is tossed once is 2/3, since there are four outcomes that satisfy this condition out of a total of six possible outcomes.