P varies inversely as the square of W. When W = 4, P = 9. Find the value of P when W = 9
Question 1 Report
P varies inversely as the square of W. When W = 4, P = 9. Find the value of P when W = 9
Answer Details
The problem states that P varies inversely as the square of W, which means that as W increases, P decreases, and vice versa. We can write this relationship as P = k/W^2, where k is the constant of proportionality.
To solve for k, we can use the given information that when W = 4, P = 9. Plugging these values into the equation, we get:
9 = k/4^2
9 = k/16
k = 9 x 16
k = 144
Now that we know k, we can use the equation to find P when W = 9:
P = 144/9^2
P = 144/81
P = 16/9
Therefore, the value of P when W = 9 is 16/9.
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