What amount of mercury would be liberated if the same quantity of electricity that liberates 0.65g of zinc is applied?
Answer Details
Zn2+ + 2e- → Zn 2F will be liberated 65g of Zn, if 0.65gm of Zn is liberated, the quantity of electricity used X = (0.65/65) * 2 = 0.02F ∴ Hg+ + e- → Hg1 i.e 1F → 201gm of Hg ∴ 0.02 will liberated Y = (0.02/1) * 201 = 4.02g