A fixed mass of gas has a volume of 92cm3 at 3 oC. When will be its volume at 18 oC if the pressure remains constant

This is a problem about the ideal gas law, which relates the pressure, volume, temperature, and amount of a gas. The equation for the ideal gas law is PV = nRT, where P is the pressure, V is the volume, n is the number of moles of gas, R is the ideal gas constant, and T is the temperature in Kelvin. To solve this problem, we are given the initial volume V1, initial temperature T1, and final temperature T2. We are also told that the pressure remains constant, which means that P1 = P2. Since the amount of gas is fixed, we can assume that n1 = n2. Using the ideal gas law, we can write: P1V1 = n1RT1 P2V2 = n2RT2 Since n1 = n2, we can simplify to: P1V1/T1 = P2V2/T2 We can solve for V2 by rearranging the equation: V2 = V1(T2/T1) Plugging in the given values, we get: V2 = 92 cm^3 * (291 K / 276 K) ≈ 97.0 cm^3 Therefore, the answer is 97.0 cm^3.