The solubility of a salt of molar mass 101g at 20oC is 0.34 mol dm-3. If 3.40g of the salt is dissolved completely in 250cm3 of water in a beaker, the resul...

Answer Details

To determine whether the resulting solution is a suspension, saturated, unsaturated, or supersaturated, we need to compare the amount of salt dissolved in water with its maximum solubility at that temperature. First, we need to calculate the maximum amount of salt that can dissolve in 250 cm³ of water at 20°C using the given solubility: 0.34 mol dm⁻³ = 0.34 mol / 1000 cm³ Maximum amount of salt that can dissolve in 250 cm³ of water = 0.34 x 250 / 1000 = 0.085 mol Next, we need to compare the maximum amount of salt that can dissolve in water with the actual amount of salt dissolved in 250 cm³ of water: Amount of salt dissolved in 250 cm³ of water = 3.40 g / 101 g/mol = 0.0337 mol Since the actual amount of salt dissolved in water (0.0337 mol) is less than the maximum amount of salt that can dissolve in water (0.085 mol), the resulting solution is unsaturated. Therefore, the answer is Unsaturated.