If two charged plates are maintained at a potential difference of 3 kv, the work done in taking a charge of 600 µC across the field is?

Answer Details

The work done in taking a charge across a potential difference is given by the formula:
work = charge x potential difference
In this case, the charge taken is 600 µC (which is 600 x 10^-6 C) and the potential difference between the plates is 3 kV (which is 3 x 10^3 V). Therefore, substituting these values into the above formula, we get:
work = 600 x 10^-6 C x 3 x 10^3 V = 1.8 J
Hence, the work done in taking a charge of 600 µC across the field is 1.8 J. Therefore, the answer is 1.8 J.