A 40KW electric cable was uses to transmit electricity through a resistor of resistance 2.00Ω at 800V. The power loss as internal energy is

A 40KW electric cable was uses to transmit electricity through a resistor of resistance 2.00Ω at 800V. The power loss as internal energy is

Answer Details

In general, Power = IV;$⟹40KW=IV\text{Therefore}40000=1\times 800⟹I=\frac{40000}{800}=50A,\text{tune the current through}$

Resistor = 50A
power loss= I2R = 502 x 2
= 2500 x 2 = 5.0 x 103W