Question 1 Report

The figure above shows 4 forces 3N, 10N, 3√3N and 6N acting on a particle P. The resultant of he four forces is

Answer Details

Resolution of force: Total vertical upward force: = 3√3 + 10 cos 60o = 3√3 + 5. Total downward force = 6 cos 30o = 6 x √(3/2) = 3√3 Total horizontal forces towards right; = 3N + cos 30o = 3N + 10 x √(3/2) = 3N + 5√3 Total horizontal forces towards left: = 6 cos 60o = 6 x 0.5 = 3.0N Summary: Vertical resultant forces upward: = 3√3 + 5 - 3√3 = 5N Horizontal resultant forces towards right: = 3N + 5√3 - 3√3 = 5N Horizontal resultant force towards right = 3N + 5√3 - 3N = 5√3N

∴ R2 = 52 + (5√3)2= 25 + 25 x 3= 100∴ R = √100= 10N