A gramophone record takes 5s to reach its constant angular velocity of 4π π rads-1 from rest. Find its constant angular acceleration.

A gramophone record takes 5s to reach its constant angular velocity of 4$\pi$ rads-1 from rest. Find its constant angular acceleration.

Answer Details

The gramophone record has an initial angular velocity of 0 and reaches a final angular velocity of 4π π  rads-1 in 5 seconds. The constant angular acceleration can be found using the following formula: angular acceleration = (final angular velocity - initial angular velocity) / time Substituting the given values, we get: angular acceleration = (4π π  rads-1 - 0) / 5s = 4π π  rads-1 / 5s = 0.8π π  rads-2 Therefore, the constant angular acceleration is 0.8π π  rads-2.