A gramophone record takes 5s to reach its constant angular velocity of \(4\pi\ \text{rads}^{-1}\) from rest. Find its constant angular acceleration.
Question 1 Report
A gramophone record takes 5s to reach its constant angular velocity of \(4\pi\ \text{rads}^{-1}\) from rest. Find its constant angular acceleration.
Answer Details
The gramophone record has an initial angular velocity of 0 and reaches a final angular velocity of 4π
π
rads-1 in 5 seconds. The constant angular acceleration can be found using the following formula:
angular acceleration = (final angular velocity - initial angular velocity) / time
Substituting the given values, we get:
angular acceleration = (4π
π
rads-1 - 0) / 5s = 4π
π
rads-1 / 5s = 0.8π
π
rads-2
Therefore, the constant angular acceleration is 0.8π
π
rads-2.
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