Question 1 Report
Fig. 1.1 shows two identical aluminium cans, each containing 200 cm³ of hot water. Can A has a matte black painted surface. Can B has a polished silver surface. A thermometer is placed in each can.
Fig. 1.2 shows the thermometer reading at the start of the experiment.
The temperature of the water in each can is recorded every 2 minutes for 10 minutes. The results are shown in Table 1.1.
| Time / min | 0 | 2 | 4 | 6 | 8 | 10 |
|---|---|---|---|---|---|---|
| Temperature of can A / °C | 74 | 67 | 61 | 56 | 52 | |
| Temperature of can B / °C | 77 | 72 | 68 | 64 | 61 |
(a) Record the initial temperature of the water from the thermometer in Fig. 1.2. Write this value in Table 1.1. [1]
(b) Calculate the total temperature drop over 10 minutes for each can.
can A: temperature drop = .................. °C [1]
can B: temperature drop = .................. °C [1]
(c) On the grid below, plot a graph of temperature against time for both cans. Draw two smooth curves and label each one A and B. [3]
(d) State which can cools at a faster rate. [1]
(e) Calculate the average rate of cooling for can A between 0 and 10 minutes. Include the unit. [2]
(f) Explain why one can emits thermal radiation at a greater rate than the other. [2]
(a) Reading the thermometer in Fig. 1.2: the liquid column sits at the second minor division above the 80 °C mark. Each major division spans 20 °C with one minor division in between (every 10 °C), so the reading is:
\[ \text{Initial temperature} = 82\,°\text{C} \quad [1] \]
(b) Temperature drop over 10 minutes:
\[ \text{Can A: } 82 - 52 = 30\,°\text{C} \quad [1] \]
\[ \text{Can B: } 82 - 61 = 21\,°\text{C} \quad [1] \]
(c) Plotting both cooling curves on the grid:
Can A points plotted correctly [1]; Can B points plotted correctly [1]; two smooth curves drawn and labelled A and B [1]. Both curves start at 82 °C and decrease, with A falling more steeply.
(d) Can A (matte black surface) cools at a faster rate. [1]
Its temperature drops by 30 °C in 10 minutes, compared to only 21 °C for Can B.
(e) Average rate of cooling for Can A:
\[ \text{rate} = \frac{\text{temperature drop}}{\text{time}} = \frac{30\,°\text{C}}{10\,\text{min}} \quad [1] \]
\[ \text{rate} = 3.0\,°\text{C per minute} \quad [1] \]
(f) Dark, matte surfaces are better emitters of infrared radiation than shiny, polished surfaces. [1]
Can A (matte black) radiates thermal energy to its surroundings at a higher rate. Can B (polished silver) reflects radiation internally and emits poorly, retaining more of its thermal energy. This is why Can A loses heat faster. [1]
The same surface properties that make a good absorber also make a good emitter. This is a general principle of thermal radiation.
Everything you need to excel in your exams