Further Pure Mathematics - 4PM1 PearsonEdexcel

Rationalising The Denominator

Akopọ

Surds are precise, but a square root lurking in a denominator makes an expression harder to read, harder to compare and harder to simplify. Rationalising the denominator is the technique that removes every irrational part from the bottom of a fraction, leaving a clean rational number underneath.

You will learn two core moves: multiplying by the surd itself when the denominator is a single term, and multiplying by the conjugate when it contains two terms. Both rest on one elegant algebraic fact: the product of conjugate surds is always rational. Master these and you will handle every rationalisation question Edexcel can set.

Awọn Afojusun

  1. Rationalise the denominator of expressions involving surds

Akọ̀wé Ẹ̀kọ́

When you divide by an irrational number you get an expression that is awkward to evaluate, difficult to compare and almost impossible to simplify further. Rationalising the denominator rewrites the fraction so that only rational numbers appear below the line. The value of the expression does not change; only its form improves.

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Oriire fun ipari ẹkọ lori Rationalising The Denominator. Ni bayi ti o ti ṣawari naa awọn imọran bọtini ati awọn imọran, o to akoko lati fi imọ rẹ si idanwo. Ẹka yii nfunni ni ọpọlọpọ awọn adaṣe awọn ibeere ti a ṣe lati fun oye rẹ lokun ati ṣe iranlọwọ fun ọ lati ṣe iwọn oye ohun elo naa.

Iwọ yoo pade adalu awọn iru ibeere, pẹlu awọn ibeere olumulo pupọ, awọn ibeere idahun kukuru, ati awọn ibeere iwe kikọ. Gbogbo ibeere kọọkan ni a ṣe pẹlu iṣaro lati ṣe ayẹwo awọn ẹya oriṣiriṣi ti imọ rẹ ati awọn ogbon ironu pataki.

Lo ise abala yii gege bi anfaani lati mu oye re lori koko-ọrọ naa lagbara ati lati ṣe idanimọ eyikeyi agbegbe ti o le nilo afikun ikẹkọ. Maṣe jẹ ki awọn italaya eyikeyi ti o ba pade da ọ lójú; dipo, wo wọn gẹgẹ bi awọn anfaani fun idagbasoke ati ilọsiwaju.

  1. What is the conjugate of 3 + sqrt(5)? A) 3 + sqrt(5) B) 3 - sqrt(5) C) -3 + sqrt(5) D) -3 - sqrt(5) Answer: B
  2. Rationalise 1 / sqrt(2). Which is correct? A) sqrt(2) B) sqrt(2) / 4 C) sqrt(2) / 2 D) 2 / sqrt(2) Answer: C
  3. Which identity makes the conjugate method work? A) (a + b)^2 = a^2 + 2ab + b^2 B) (a + b)(a - b) = a^2 - b^2 C) a^2 + b^2 = (a + b)^2 D) (a - b)^2 = a^2 - 2ab + b^2 Answer: B
  4. What is 8 / (2 * sqrt(2)) in its simplest rationalised form? A) 2 * sqrt(2) B) 4 * sqrt(2) C) sqrt(2) D) 4 / sqrt(2) Answer: A
  5. Rationalise 1 / (sqrt(6) - sqrt(5)). The denominator becomes: A) 1 B) 11 C) sqrt(30) D) 6 - 5 Answer: A

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Gba ohun elo Green Bridge CBT sori foonu tabi kọmputa rẹ lati ri awọn akọsilẹ ẹkọ ni kikun, awọn ibeere adaṣe, ati diẹ sii.

Awọn akọsilẹ ẹkọ ni kikun pẹlu awọn aworan apejuwe
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O wa lori ohun elo Green Bridge

Gba ohun elo Green Bridge CBT sori foonu tabi kọmputa rẹ lati ri awọn akọsilẹ ẹkọ ni kikun, awọn ibeere adaṣe, ati diẹ sii.

Awọn akọsilẹ ẹkọ ni kikun pẹlu awọn aworan apejuwe
Oluranlọwọ ẹkọ ti AI ṣe agbara rẹ
Kọ ẹkọ laisi intanẹẹti, nigbakugba, nibikibi
O wa lori Android, Windows, macOS, ati Linux

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