Mathematics - International - 0607 CIE

Surds

Akopọ

A surd is a root that cannot be simplified to a whole number, such as \(\sqrt{2}\) or \(\sqrt{5}\). Surds let you keep answers exact rather than rounding, which matters whenever a question asks for an exact value, and they are the natural language of Pythagoras and trigonometry results.

In this lesson (Extended tier) you will simplify surds, multiply and add them where possible, and rationalise a denominator so that no surd is left underneath a fraction. These techniques keep working tidy and answers exact.

Awọn Afojusun

  1. Understand and use surds, including simplifying expressions.
  2. Rationalise the denominator.

Akọ̀wé Ẹ̀kọ́

Writing \(\sqrt{50}\) as \(5\sqrt{2}\) is both neater and exact, and leaving an answer as a surd avoids the rounding error a decimal would introduce. Surds appear throughout geometry and trigonometry, so handling them confidently keeps later work exact.

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Gba ohun elo Green Bridge CBT sori foonu tabi kọmputa rẹ lati ri awọn akọsilẹ ẹkọ ni kikun, awọn ibeere adaṣe, ati diẹ sii.

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Ìdánwò Ẹ̀kọ́

Oriire fun ipari ẹkọ lori Surds. Ni bayi ti o ti ṣawari naa awọn imọran bọtini ati awọn imọran, o to akoko lati fi imọ rẹ si idanwo. Ẹka yii nfunni ni ọpọlọpọ awọn adaṣe awọn ibeere ti a ṣe lati fun oye rẹ lokun ati ṣe iranlọwọ fun ọ lati ṣe iwọn oye ohun elo naa.

Iwọ yoo pade adalu awọn iru ibeere, pẹlu awọn ibeere olumulo pupọ, awọn ibeere idahun kukuru, ati awọn ibeere iwe kikọ. Gbogbo ibeere kọọkan ni a ṣe pẹlu iṣaro lati ṣe ayẹwo awọn ẹya oriṣiriṣi ti imọ rẹ ati awọn ogbon ironu pataki.

Lo ise abala yii gege bi anfaani lati mu oye re lori koko-ọrọ naa lagbara ati lati ṣe idanimọ eyikeyi agbegbe ti o le nilo afikun ikẹkọ. Maṣe jẹ ki awọn italaya eyikeyi ti o ba pade da ọ lójú; dipo, wo wọn gẹgẹ bi awọn anfaani fun idagbasoke ati ilọsiwaju.

  1. Simplify √50. A. 5√2 B. 2√5 C. 25√2 D. 10√5 Answer: A
  2. Work out √3 x √12. A. √15 B. 6 C. 36 D. 4√3 Answer: B
  3. Simplify 2√5 + 3√5. A. 5√10 B. 6√5 C. 5√5 D. 5 Answer: C
  4. Rationalise the denominator of 1/√2. A. √2 B. 2/√2 C. √2/2 D. 1/2 Answer: C
  5. Which expression cannot be simplified? A. √8 B. √2 + √3 C. √2 x √8 D. 4√3 - √3 Answer: B

O wa lori ohun elo Green Bridge

Gba ohun elo Green Bridge CBT sori foonu tabi kọmputa rẹ lati ri awọn akọsilẹ ẹkọ ni kikun, awọn ibeere adaṣe, ati diẹ sii.

Awọn akọsilẹ ẹkọ ni kikun pẹlu awọn aworan apejuwe
Oluranlọwọ ẹkọ ti AI ṣe agbara rẹ
Kọ ẹkọ laisi intanẹẹti, nigbakugba, nibikibi
O wa lori Android, Windows, macOS, ati Linux

O wa lori ohun elo Green Bridge

Gba ohun elo Green Bridge CBT sori foonu tabi kọmputa rẹ lati ri awọn akọsilẹ ẹkọ ni kikun, awọn ibeere adaṣe, ati diẹ sii.

Awọn akọsilẹ ẹkọ ni kikun pẹlu awọn aworan apejuwe
Oluranlọwọ ẹkọ ti AI ṣe agbara rẹ
Kọ ẹkọ laisi intanẹẹti, nigbakugba, nibikibi
O wa lori Android, Windows, macOS, ati Linux

Ṣe Adaṣe Awọn Ibeere Idanwo Adaṣe

Ṣe o fẹ ṣe adaṣe awọn ibeere idanwo adaṣe nipa Surds? Ṣe igbasilẹ ohun elo Green Bridge CBT lati wọle si awọn ibeere idanwo adaṣe ati awọn ayẹwo adaṣe kikun fun koko-ọrọ yii.

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