Chemistry (9-1) - 0971 CIE

Reversible Reactions And Equilibrium

Akopọ

Most reactions seem to run one way and stop, but a surprising number can go forwards and backwards. Heat blue hydrated copper(II) sulfate and it turns white; add water and the blue returns. That single demonstration is the gateway to one of chemistry's most powerful ideas: dynamic equilibrium, and the industrial processes that depend on it.

In this lesson you will meet reversible reactions and the special arrow that marks them, learn what it means for a closed system to reach equilibrium, and see how changing temperature, pressure and concentration shift the balance. You will then apply all of this to the Haber process for ammonia and the Contact process for sulfuric acid.

Awọn Afojusun

  1. State that some chemical reactions are reversible as shown by the symbol ⇌.
  2. Describe how changing the conditions can change the direction of a reversible reaction for: (a) the effect of heat on hydrated compounds (b) the addition of water to anhydrous compounds limited to copper(II) sulfate and cobalt(II) chloride.
  3. [Supplement] State that a reversible reaction in a closed system is at equilibrium when: (a) the rate of the forward reaction is equal to the rate of the reverse reaction (b) the concentrations of reactants and products are no longer changing.
  4. [Supplement] Predict and explain, for a reversible reaction, how the position of equilibrium is affected by: (a) changing temperature (b) changing pressure (c) changing concentration (d) using a catalyst using information provided.
  5. [Supplement] State the symbol equation for the production of ammonia in the Haber process, N (g) + 3H (g) 2NH (g) 2 2 3.
  6. [Supplement] State the sources of the hydrogen (methane) ⇌ and nitrogen (air) in the Haber process.
  7. [Supplement] State the typical conditions in the Haber process as 450 °C, 20 000 kPa / 200 atm and an iron catalyst.
  8. [Supplement] State the symbol equation for the conversion of sulfur dioxide to sulfur trioxide in the Contact process, 2SO (g) + O (g) 2SO (g) 2 2 3.
  9. [Supplement] State the sources of the sulfur dioxide (burning ⇌ sulfur or roasting sulfide ores) and oxygen (air) in the Contact process.
  10. [Supplement] State the typical conditions for the conversion of sulfur dioxide to sulfur trioxide in the Contact process as 450 °C, 200 kPa / 2 atm and a vanadium(V) oxide catalyst.
  11. [Supplement] Explain, in terms of rate of reaction and position of equilibrium, why the typical conditions stated are used in the Haber process and in the Contact process, including safety considerations and economics.

Akọ̀wé Ẹ̀kọ́

Two of the world's most important industrial reactions, making ammonia for fertilisers and making sulfuric acid, are reversible. Choosing the right conditions to get a good yield at an acceptable rate and cost is a real-world balancing act, and it is examined in detail. Understanding equilibrium turns these processes from facts to memorise into ideas you can reason about.

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Iwọ yoo pade adalu awọn iru ibeere, pẹlu awọn ibeere olumulo pupọ, awọn ibeere idahun kukuru, ati awọn ibeere iwe kikọ. Gbogbo ibeere kọọkan ni a ṣe pẹlu iṣaro lati ṣe ayẹwo awọn ẹya oriṣiriṣi ti imọ rẹ ati awọn ogbon ironu pataki.

Lo ise abala yii gege bi anfaani lati mu oye re lori koko-ọrọ naa lagbara ati lati ṣe idanimọ eyikeyi agbegbe ti o le nilo afikun ikẹkọ. Maṣe jẹ ki awọn italaya eyikeyi ti o ba pade da ọ lójú; dipo, wo wọn gẹgẹ bi awọn anfaani fun idagbasoke ati ilọsiwaju.

  1. Which symbol shows that a reaction is reversible? A. -> B. = C. the double arrow (reversible) symbol D. + Answer: C
  2. Hydrated copper(II) sulfate is: A. white B. blue C. pink D. green Answer: B
  3. At dynamic equilibrium in a closed system: A. the reaction has stopped B. only the forward reaction occurs C. forward and reverse rates are equal D. concentrations keep rising Answer: C
  4. The typical conditions for the Haber process are: A. 450 C, 200 kPa, vanadium(V) oxide B. 450 C, 20 000 kPa, iron C. 25 C, 100 kPa, platinum D. 1000 C, 20 000 kPa, nickel Answer: B
  5. Adding a catalyst to a reversible reaction at equilibrium: A. increases the yield of product B. shifts equilibrium to the right C. does not change the position of equilibrium D. stops the reverse reaction Answer: C

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