Science - Combined - 0653 CIE

Electrical Quantities Continued

Akopọ

Every time you switch on a light, charge is pushed around a circuit by a source, gives up energy in the bulb, and returns for more. The push is the electromotive force, the energy given up per coulomb is the potential difference, and the opposition to the flow is the resistance. Master these three and you can analyse and cost almost any circuit.

In this topic you will define e.m.f. and potential difference, use voltmeters, measure and calculate resistance, and link power and energy to current and voltage. You will sketch the current-voltage graphs of a resistor, a lamp and a diode, and learn to work out the cost of running appliances in kilowatt-hours.

Awọn Afojusun

  1. [Core] Know that electric current is related to the flow of charge
  2. [Core] Know that electric current in metals is related to the flow of electrons
  3. [Core] Describe the use of ammeters (analogue and digital) with different ranges
  4. [Core] Know the difference between direct current (d.c.) and alternating current (a.c.)
  5. [Core] Describe the voltage of the source as the cause of current in the circuit
  6. [Core] Know that the voltage of the source is shared between the components in a series circuit
  7. [Core] Describe the use of voltmeters (analogue and digital) with different ranges
  8. [Core] Recall and use the equation for resistance V R = I
  9. [Supplement] Define electric current as the charge passing a point per unit time; recall and use the equation Q I = t
  10. [Supplement] Describe electrical conduction in metals in terms of the movement of delocalised (mobile) electrons
  11. [Supplement] State that conventional current is from positive to negative and that the flow of electrons is from negative to positive
  12. [Supplement] Define electromotive force (e.m.f.) as the electrical work done by a source in moving a unit charge around a complete circuit
  13. [Supplement] Know that e.m.f. is measured in volts (V)
  14. [Supplement] Define potential difference (p.d.) as the work done by a unit charge passing between two points in a circuit
  15. [Supplement] Know that the p.d. between two points is measured in volts (V)
  16. [Supplement] Recall and use the following relationship for a metallic electrical conductor: (a) resistance is directly proportional to length (b) resistance is inversely proportional to cross-sectional area

Akọ̀wé Ẹ̀kọ́

Electrical quantities run through every device and every electricity bill. Engineers size wires, rate appliances and design circuits using exactly these equations. In the exam this topic is rich in marks: definitions, graph sketches, and a string of calculations for resistance, power, energy and cost.

O wa lori ohun elo Green Bridge

Gba ohun elo Green Bridge CBT sori foonu tabi kọmputa rẹ lati ri awọn akọsilẹ ẹkọ ni kikun, awọn ibeere adaṣe, ati diẹ sii.

Awọn akọsilẹ ẹkọ ni kikun pẹlu awọn aworan apejuwe
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Ìdánwò Ẹ̀kọ́

Oriire fun ipari ẹkọ lori Electrical Quantities Continued. Ni bayi ti o ti ṣawari naa awọn imọran bọtini ati awọn imọran, o to akoko lati fi imọ rẹ si idanwo. Ẹka yii nfunni ni ọpọlọpọ awọn adaṣe awọn ibeere ti a ṣe lati fun oye rẹ lokun ati ṣe iranlọwọ fun ọ lati ṣe iwọn oye ohun elo naa.

Iwọ yoo pade adalu awọn iru ibeere, pẹlu awọn ibeere olumulo pupọ, awọn ibeere idahun kukuru, ati awọn ibeere iwe kikọ. Gbogbo ibeere kọọkan ni a ṣe pẹlu iṣaro lati ṣe ayẹwo awọn ẹya oriṣiriṣi ti imọ rẹ ati awọn ogbon ironu pataki.

Lo ise abala yii gege bi anfaani lati mu oye re lori koko-ọrọ naa lagbara ati lati ṣe idanimọ eyikeyi agbegbe ti o le nilo afikun ikẹkọ. Maṣe jẹ ki awọn italaya eyikeyi ti o ba pade da ọ lójú; dipo, wo wọn gẹgẹ bi awọn anfaani fun idagbasoke ati ilọsiwaju.

  1. The resistance of a component carrying 2 A with 12 V across it is: A. 24 ohm B. 6 ohm C. 0.17 ohm D. 10 ohm Answer: B
  2. A voltmeter should be connected: A. in series with the component B. in parallel with the component C. before the cell only D. it does not matter Answer: B
  3. The I-V graph of a resistor of constant resistance is: A. a curve flattening off B. a straight line through the origin C. zero one way only D. a horizontal line Answer: B
  4. A 60 W lamp runs for 1 hour. The energy used is: A. 60 J B. 0.06 kW h C. 60 kW h D. 3600 kW h Answer: B
  5. 1 kilowatt-hour is equal to: A. 1000 J B. 3600 J C. 3.6 MJ D. 60 J Answer: C

O wa lori ohun elo Green Bridge

Gba ohun elo Green Bridge CBT sori foonu tabi kọmputa rẹ lati ri awọn akọsilẹ ẹkọ ni kikun, awọn ibeere adaṣe, ati diẹ sii.

Awọn akọsilẹ ẹkọ ni kikun pẹlu awọn aworan apejuwe
Oluranlọwọ ẹkọ ti AI ṣe agbara rẹ
Kọ ẹkọ laisi intanẹẹti, nigbakugba, nibikibi
O wa lori Android, Windows, macOS, ati Linux

O wa lori ohun elo Green Bridge

Gba ohun elo Green Bridge CBT sori foonu tabi kọmputa rẹ lati ri awọn akọsilẹ ẹkọ ni kikun, awọn ibeere adaṣe, ati diẹ sii.

Awọn akọsilẹ ẹkọ ni kikun pẹlu awọn aworan apejuwe
Oluranlọwọ ẹkọ ti AI ṣe agbara rẹ
Kọ ẹkọ laisi intanẹẹti, nigbakugba, nibikibi
O wa lori Android, Windows, macOS, ati Linux

Ṣe Adaṣe Awọn Ibeere Idanwo Adaṣe

Ṣe o fẹ ṣe adaṣe awọn ibeere idanwo adaṣe nipa Electrical Quantities Continued? Ṣe igbasilẹ ohun elo Green Bridge CBT lati wọle si awọn ibeere idanwo adaṣe ati awọn ayẹwo adaṣe kikun fun koko-ọrọ yii.

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