Differentiating Products And Quotients
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You can differentiate simple powers, but real functions are often built by multiplying or dividing two expressions together. To differentiate these you need two new tools: the product rule and the quotient rule. They are the natural next step once basic differentiation is secure.
In this lesson you will learn the product rule \((uv)'=u'v+uv'\) and the quotient rule \(\left(\frac{u}{v}\right)'=\frac{u'v-uv'}{v^2}\), and apply them to worked examples. The key skill is identifying the two pieces, differentiating each, and assembling the result in the correct order, especially the subtraction in the quotient rule.
Awọn Afojusun
- Differentiate products and quotients of functions.
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Oriire fun ipari ẹkọ lori Differentiating Products And Quotients. Ni bayi ti o ti ṣawari naa awọn imọran bọtini ati awọn imọran, o to akoko lati fi imọ rẹ si idanwo. Ẹka yii nfunni ni ọpọlọpọ awọn adaṣe awọn ibeere ti a ṣe lati fun oye rẹ lokun ati ṣe iranlọwọ fun ọ lati ṣe iwọn oye ohun elo naa.
Iwọ yoo pade adalu awọn iru ibeere, pẹlu awọn ibeere olumulo pupọ, awọn ibeere idahun kukuru, ati awọn ibeere iwe kikọ. Gbogbo ibeere kọọkan ni a ṣe pẹlu iṣaro lati ṣe ayẹwo awọn ẹya oriṣiriṣi ti imọ rẹ ati awọn ogbon ironu pataki.
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- The product rule for y = uv states that dy/dx equals: A. u'v' B. u'v + uv' C. u'v - uv' D. (u'v - uv')/v^2 Answer: B
- The quotient rule for y = u/v states that dy/dx equals: A. (u'v + uv')/v^2 B. (u'v - uv')/v^2 C. (uv' - u'v)/v^2 D. u'/v' Answer: B
- Differentiate y = x^2(2x + 1). A. 4x + 1 B. 6x^2 + 2x C. 2x^2 + 2x D. 6x^2 + 1 Answer: B
- Differentiate y = x/(x + 1). A. 1 B. 1/(x + 1) C. 1/(x + 1)^2 D. x/(x + 1)^2 Answer: C
- In the quotient rule, the denominator of the result is: A. v B. v^2 C. u^2 D. uv Answer: B
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